Marks¶

A list of marks corresponding to an exam consists of sublists of two elements: the student identifier (str) and their mark (float). You may suppose that the list is not empty.

Save the following functions into the file marks.py:

Write the function search_ident() that takes a list of marks and a student identifier (str), and returns True if the given identifier belongs to the list and False otherwise. Examples:
```
>>> l = [['44444444D',8.3],['11111111A',7.25],['88888888H',4.1],['22222222B',3.8]]
>>> search_ident(l,'88888888H')
True
>>> search_ident(l,'33333333C')
False
>>> search_ident([],'11111111A')
False
```
Note

More tests are provided in the file test-marks-1.txt.
Write the function search_mark() that takes a list and a mark (float), and returns True if there is at least one student having this mark and False otherwise. Examples:
```
>>> l = [['44444444D',8.3],['11111111A',7.25],['88888888H',4.1],['22222222B',3.8]]
>>> search_mark(l,7.25)
True
>>> search_mark(l,5.0)
False
>>> search_mark([],6.5)
False
```
Note

More tests are provided in the file test-marks-2.txt.

Write the function perc_passed() that takes a list of marks, and returns the percentage (float) of students who have passed the exam. Examples:

>>> l = [['44444444D',8.3],['11111111A',7.25],['88888888H',4.1],['22222222B',3.8],['66666666F',5.3]]
>>> round(perc_passed(l), 2)
60.0
>>> l = [['3A', 5]]
>>> round(perc_passed(l), 2)
100.0
>>> l = [['1A', 2], ['2B', 1], ['3C', 4]]
>>> round(perc_passed(l), 2)
0.0

Note

More tests are provided in the file test-marks-3.txt.

Write the function best_worst_mark() that takes a list of marks, and returns the best mark (float) and the worst mark (float) in the list. Examples:

>>> l = [['44444444D',8.3],['11111111A',7.25],['88888888H',4.1],['22222222B',3.8],['66666666F',5.3]] 
>>> m, p = best_worst_mark(l)
>>> m
8.3
>>> p
3.8
>>> l = [['3A', 5]]
>>> m, p = best_worst_mark(l)
>>> m
5
>>> p
5

Note

More tests are provided in the file test-marks-4.txt.

Write the function mark_distribution() that takes a list of marks, and returns another list with 11 items that represents the marks distribution between 0 and 10. The first item in the list will be the number of marks belonging to the interval [0, 1[; the second item will be the number of marks belonging to the interval [1, 2[; and so on. The last (11th) item will contain the number of marks equal to 10. Examples:
```
>>> l = [['44444444D',8.3],['88888888H',4.1],['22222222B',4.8],['66666666F',5.3],['99999999J',10.0]]
>>> dn = mark_distribution(l)
>>> dn
[0, 0, 0, 0, 2, 1, 0, 0, 1, 0, 1]
>>> l = [['3A', 5]]
>>> dn = mark_distribution(l)
>>> dn
[0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0]
>>> l = [['1A', 2], ['2B', 1], ['3C', 4]]
>>> dn = mark_distribution(l)
>>> dn
[0, 1, 1, 0, 1, 0, 0, 0, 0, 0, 0]
```
Note

More tests are provided in the file test-marks-5.txt.

Write the function best_students() that takes a list of marks, and returns another list with the identifiers (str) of those students whose mark is 10. This list must be sorted increasingly. Examples:

>>> l = [['44444444D',8.3],['88888888H',10.0],['33333333C',10.0],['22222222B',4.8],['66666666F',5.3],['99999999J',10.0]]
>>> ld = best_students(l)
>>> ld
['33333333C', '88888888H', '99999999J']
>>> l = [['3A', 10]]
>>> ld = best_students(l)
>>> ld
['3A']
>>> l = [['3A', 5]]
>>> ld = best_students(l)
>>> ld
[]

Note

More tests are provided in the file test-marks-6.txt.

Write the function sort_ident() that takes a list of marks, and returns a list with the same items sorted by increasing identifiers. Examples:

>>> l = [['44444444D',8.3],['88888888H',10.0],['33333333C',10.0],['22222222B',4.8],['66666666F',5.3],['99999999J',10.0]]
>>> ld = sort_ident(l)
>>> ld
[['22222222B', 4.8], ['33333333C', 10.0], ['44444444D', 8.3], ['66666666F', 5.3], ['88888888H', 10.0], ['99999999J', 10.0]]

Note

More tests are provided in the file test-marks-7.txt.

Write the function sort_marks() that takes a list of marks, and returns a list with the same items sorted by increasing marks firstly and increasing identifiers secondly. Examples:
```
>>> l = [['44444444D',8.3],['88888888H',10.0],['22222222B',4.8],['66666666F',5.3]]
>>> sort_marks(l)
[['22222222B', 4.8], ['66666666F', 5.3], ['44444444D', 8.3], ['88888888H', 10.0]]
```
Note

More tests are provided in the file test-marks-8.txt.
Write the function average() that takes a list of marks, and returns the average mark (float). Examples:
```
>>> l = [['44444444D',8.3],['88888888H',10.0],['22222222B',4.8],['66666666F',5.3]]
>>> round(average(l), 2)
7.1
```
Note

More tests are provided in the file test-marks-9.txt.

Solution

A solution of these functions is provided in the file marks.py.